Forces in Equilibrium Laboratory
Analyze vector mechanics by altering weights. Calculate the unknown total internal angle (θ), then verify using the components breakdown section below.
System Status: STATIC EQUILIBRIUM
Mass Configurations
Because the central junction ring remains completely static, the system satisfies Static Equilibrium (Net Force = 0). This implies the pulling components must balance perfectly across both horizontal and vertical axes.
1. Horizontal Axis Forces Balance (X-Axis)
The left horizontal component fights off the right horizontal component:
T1 * sin(α) = T2 * sin(β)
Since hanging weights m1 and m2 create the cord tensions directly, T1 = m1 * g and T2 = m2 * g.
2. Vertical Axis Forces Balance (Y-Axis)
The vertical lift components of both cords join forces to support the central load weight (m3):
T1 * cos(α) + T2 * cos(β) = m3 * g
Current System Real-Time Analytical Calculations:
Left Tension (T1): --
Right Tension (T2): --
Center Weight (W3): --
Calculated Vector Component Angles (relative to center vertical normal):
Left Side Component Angle (α): -- | Right Side Component Angle (β): --
Total Inside Target Angle (θ) = α + β = --
Left Side Component Angle (α): -- | Right Side Component Angle (β): --
Total Inside Target Angle (θ) = α + β = --